10a^2+5a-1=0

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Solution for 10a^2+5a-1=0 equation: 



10a^2+5a-1=0

a = 10; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·10·(-1)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{65}}{2*10}=\frac{-5-\sqrt{65}}{20}
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{65}}{2*10}=\frac{-5+\sqrt{65}}{20}
$

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